Random sample and percentage
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I have a table with several data (columns and rows). I would like to take il 20% or the 10% of the data, but the sample has to be random.
As finally result, I would like the table with the random sample of the 20%.
How can I do?
回答（1 个）
Yongjian Feng
2021-7-6
Try this?
column_count = 100; % your columns
row_count = 200; % your rows
percentage_to_take = 0.2; % you take 20% of total
total_count = column_count * row_count; % total count of samples
samples_to_take = percentage_to_take * total_count;
% Use a for loop
sample = zeros(1, saamples_to_take);
for i=1:samples_to_take
c_index = randi(column_count, 1); % a random index into columnn
r_index = randi(row_count, 1); % a random index into row
% access your table
sample(i) = your_table(c_index, r_index);
end
4 个评论
Rachele Franceschini
2021-7-6
编辑：Rachele Franceschini
2021-7-6
Yongjian Feng
2021-7-6
sample is an array with 20% of the total samples.
If you need a table instead of an array, then rearrange the sample array into the table you want.
Rachele Franceschini
2021-7-6
编辑：Rachele Franceschini
2021-7-6
Yongjian Feng
2021-7-6
What is an element in your table? It is a matlab struct, or an object?
But this doesn't matter. If your_table is a table of matlab struct, then sample above is an array of matlab struct as well.
Whatever in your table is coped into the sample array. In other words, the sample array is not an array of numbers. It is an array similar to your table.
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2021-7-6
2021-7-6
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