To find integral of a function in loop

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Nadia jabeen
Nadia jabeen 2021-7-6
评论： Alan Stevens 2021-7-6
Hi,
I am calculating integral of a function 'f' with respect to lamda. I want to calculate variable 'q' for all possible values given in range of variable 'x'. upper limit and lower limit of variable lamda is as same as in variable 'x'. But matlab function given an error. kingly ghide me. or matlab show output of a single value. I want to do these calculations as a vector.
x = [600*10^-9:5*10^-9:800*10^-9];
for i = 1:numel(x)
N=(15.*z.*T*((h.*c).^3));
f=@(lamda)((Pi.^4).*(lamda.^4)*(k.^3));
q = integral(f,6e-7, x);
F=(N./q);
end

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采纳的回答

Alan Stevens
Alan Stevens 2021-7-6
Try replacing
q = integral(f,6e-7, x);
with
q(i) = integral(f,6e-7, x(i));
  2 个评论
Nadia jabeen
Nadia jabeen 2021-7-6
Now error has been removed. But only one value is appear for q(i). I want to plot a graph for all values of q(i). how can I store all these values in one variable?
Alan Stevens
Alan Stevens 2021-7-6
Ran in:
q holds all the results! For example:
x = [600*10^-9:5*10^-9:800*10^-9];
% Arbitrary data - replace with your own
N=1; %(15.*z.*T*((h.*c).^3));
k = 10^3;
lambda = 10^4;
f=@(lamda)((pi.^4).*(lamda.^4)*(k.^3));
for i = 1:numel(x)
q(i) = integral(f,6e-7, x(i));
F=(N./q);
end
plot(x,q),grid
xlabel('x'),ylabel('q')

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