How to skip parameters in a function call

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Dominik Hildebrand
评论： Star Strider 2021-7-7
Hello,
i'd like to make a function that can be called even if only a part of its input parameters are defined in the call.
I.e.:
Function definition is something along this lines:
function [ret] = fun(a, b, c, d, e)
if ~exist('a','var')
% parameter a does not exist, so default it to something
a = 0;
end
if ~exist('b','var')
...
ret = [a,b,c,d,e];
return;
The function call should work something like this:
test_call_1 = fun(a=1,b=2,d=3,e=4); (here parameter c is not specified)
test_call_2 = fun(e=4); (here only parameter e is specified)
My function is already able to initialize any missing parameters with default values. I know about using "~" to specify that a parameter is skipped. However, this only works for defining the function, not when calling it (as is required here).
Any help is highly appriciated :)

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采纳的回答

Star Strider
Star Strider 2021-7-7
See the documentation section on Support Variable Number of Inputs for a demonstration of how to do that.
  4 个评论
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Dominik Hildebrand
Dominik Hildebrand 2021-7-7
Thank you again for your help :D
I feel your solution is as good as it gets, but for sake of completness ill include my final "draft" as well:
function [ ret ] = fun(a, b, c, d)
default_param = 0;
if ~exist('a','var') || isempty(a)
a = default_param;
end
if ~exist('b','var') || isempty(b)
b = default_param;
end
if ~exist('x','var') || isempty(x)
c = default_param;
end
if ~exist('c','var') || isempty(c)
d = default_param;
end
ret = [a,b,c,d];
return;

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