Determine the length of a 3D cell array (?) within a struct

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Ka
Ka 2013-9-17
Hi together,
you find a MATLAB file in the dropbox-link, containing a 1x1 struct M:
https://www.dropbox.com/sh/a7ezk1v4pmd7ywz/3QiRY4XunO
This struct contains cell-arrays d00 to d15 (I'm not sure if these are cell arrays or something else). Each d** has three dimensions.
The first two dimensios are 3 and 4 (3x4). The third dimension is varying from d** to d**.
I want to extract the entries of the third dimension within a loop. Therefor I have to determine the lentgh of this third dimension for every d**.
Somebody can give me some advice?
Thanks a lot for help in advance! Ka Me

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采纳的回答

Jan
Jan 2013-9-17
The solution would be trivial, if you avoid using "d00", "d01" etc as names of the variables. Hiding an index in the name is a very bad idea, which provokes such troubles. Better use a cell: d{1}, d{2}, ... Then:
dim3 = cellfun('size', d, 3)

更多回答（2 个）

Ka
Ka 2013-9-17
Thanks a lot for the answer, Jan Simon.
You are right about the indexing within the name. However, I am using the program of someone else and I am not sure if I can manage to change the naming if it's a bit confusing.
What you suggest is making a cell array d with dimension 1x15, i.e. entries 0 to 14. Each entry contains a three dimensional matrix 3x4x?. Is this what you mean?
When I then use
dim3 = cellfun('size', d, 3)
Will I get the third dimension of each of the 15 d-entries?
If I am not able to change the naming, is there a another way doing it?
Thanks again!
Ka
Ka 2013-9-17
I just found out that you can get the dimensions of this d-cell-arrays by dynamic adressing:
size(M.d**)
= 3 4 ...
Thanks for commenting again!

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