how can i find x value from given y (6th degree polynomial)

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y = [7 12 18 27 35 39];
p1 = 3.7739e-21
p2 = -6.5969e-17
p3 = 2.2715e-13
p4 = 1.1034e-09
p5 = -4.8986e-06
p6 = 0.010416
p7 = -0.70896
y = p1*x^6 + p2*x^5+p3*x^4+p4*x^3+p5*x^2+p6*x+p7;

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Matt J
Matt J 2021-7-9
x=roots([p1,p2,p3,p4,p5,p6,p7-y])
  9 个评论
Walter Roberson
Walter Roberson 2021-12-19
format long g
p = [3.7769e-21, -6.6055e-17, 2.2806e-13, 1.0989e-09, -4.8887e-06, 0.010408, -0.71229];
R = roots(p)
R =
9350.21416809902 + 1915.74457506144i 9350.21416809902 - 1915.74457506144i -4499.3555970064 + 0i 1608.69399831728 + 1978.77107818079i 1608.69399831728 - 1978.77107818079i 70.7499925489447 + 0i
realroots = R(imag(R)==0)
realroots = 2×1
1.0e+00 * -4499.3555970064 70.7499925489447
syms x
poly = poly2sym(p)
poly = 
fplot([poly,0], [-4750 250])
It is a degree 6 polynomial in real coefficients. There are always going to be an even number of real roots: in this case there are two real roots. You can never get just one real root for a polynomial of even order that has real coefficients.
firrou bouteflika
firrou bouteflika 2021-12-19
i see thank you and i just realized i can use polyval
h = polyval(p,[16.27 27.9 41.86 62.79 81.39 90.69])

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