Why Does int() of rectangularPulse Return NaN?
显示 更早的评论
syms t real
x(t) = rectangularPulse(0,1,t);
int(x(t),t,0,5)
int(x(t),t,0,inf)
int(x(t),t,-10,10)
int(x(t),t,-inf,inf)
Any ideas why those two cases return NaN?
采纳的回答
Work-around:
syms b x t real
assume(b>=0)
y(t) = rectangularPulse(x,1,t)
z = int(y,t,0,b)
limit(z, b, inf)
4 个评论
Paul
2021-7-9
Walter Roberson
2021-7-10
编辑：Walter Roberson
2021-7-10
I am not sure why this is happening. You can read the internal code for rectangularPulse by using
regexprep(char(feval(symengine, 'expose', 'rectangularPulse')),'\\n','\n')
but that doesn't tell you anything about how it integrates. The symbolic integration routine is too large for me to chase through.
Walter Roberson
2021-7-10
I have a suspicion that somewhere along the way, a dirac(0) is getting invoked.
更多回答（0 个）
类别
在 帮助中心 和 File Exchange 中查找有关 Creating and Concatenating Matrices 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
Translated by 
