How to find the index of any maximum matrix?

1 次查看（过去 30 天）
vimal kumar chawda
评论： DGM 2021-7-11
I have matrix X=radn(20)
I need the index or position in column and row of the maximum value.
X =rand(20)
How can I ?
  2 个评论
Image Analyst
Image Analyst 2021-7-11
Wow, 107 tags, if I conted correctly. I think that must be a reconrd. It must have taken you more time to enter all those than to just look up max() in the help. I'll show you how to do it in my answer below.
Stephen23
Stephen23 2021-7-11
@vimal kumar chawda: please do not add 107 completely unrelated tags to your questions.
You might not use tags, but you are not the only user of this forum, and some of us certainly do use tags.

请先登录，再进行评论。

请先登录，再回答此问题。

采纳的回答

DGM
DGM 2021-7-9
编辑：DGM 2021-7-9
Ran in:
s = [10 10];
x = randi(100,s)
x = 10×10
40 81 9 67 90 11 44 79 79 56 2 53 68 82 7 42 35 39 51 95 60 22 51 18 47 6 44 83 38 49 57 44 87 24 6 41 59 83 53 94 74 54 17 10 43 2 72 27 16 46 18 60 91 20 13 24 77 38 9 21 22 8 47 100 70 7 42 88 27 17 79 69 38 11 59 80 79 89 68 10 92 92 77 89 49 64 98 97 74 61 50 69 93 52 28 43 4 61 15 96
[~,idx] = max(x(:)) % this gets the linear index
idx = 37
[row col] = ind2sub(s,idx) % if you want subscripts instead
row = 7
col = 4
Of course, that's only the first instance of the maximal value.
  4 个评论
显示 2更早的评论
Image Analyst
Image Analyst 2021-7-11
Actually since his question used randn() which will give unique floating point values and only one max value, not several, your suggestion to use max() is fine.
DGM
DGM 2021-7-11
I just used randi so that the matrix was easier to read by eye and fit better on the page. The fact that it allows for frequent duplicates was what prompted me to mention the behavior.

请先登录，再进行评论。

更多回答（1 个）

Image Analyst
Image Analyst 2021-7-11
@vimal kumar chawda, try this:
m = randi(9, 5, 5)
maxValue = max(m(:))
% Find out what rows and columns the max occurs in.
% Works even if the max occurs in more than one place
% unlike the index the second output argument of max() gives you.
[rowsOfMax, columnsOfMax] = find(m == maxValue)
You'll see:
m =
3 5 7 9 8
7 9 3 5 3
6 4 5 2 8
2 6 7 2 3
2 3 9 3 9
maxValue =
9
rowsOfMax =
2
5
1
5
columnsOfMax =
2
3
4
5
Like I said, it's a more robust solution than using max() alone.

类别

在 Help Center 和 File Exchange 中查找有关 Matrix Indexing 的更多信息

标签

产品


版本

R2021a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by