When creating a table, how do I specify the dimensions of a particular variable?

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Rafael Cordero
Rafael Cordero 2021-7-11
回答： Steven Lord 2021-7-11
Hello all,
Lets say Im defining an empty table as so:
my_table = table('Size', [0,7], 'VariableNames', ...
{'name', 'window', 'fs', ...
'x', 'y', 'z', 'mag'}, ...
'VariableTypes', ...
{'string', 'double', 'double', ...
'double', 'double', 'double', 'double'});
The variable that I want to put in in 'window' is actually a 1x2 double. But when I set it:
my_table.window(1) = [1 4];
I get the error:
Unable to perform assignment because the size of the left side is 1-by-1 and the size of the right side is 1-by-2.
So: how do I specify that my 'window' is actually 1x2?
Many thanks

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采纳的回答

Steven Lord
Steven Lord 2021-7-11
Ran in:
my_table = table('Size', [0,7], 'VariableNames', ...
{'name', 'window', 'fs', ...
'x', 'y', 'z', 'mag'}, ...
'VariableTypes', ...
{'string', 'double', 'double', ...
'double', 'double', 'double', 'double'});
my_table.window(1, 1:2) = [1 4]
Warning: The assignment added rows to the table, but did not assign values to all of the table's existing variables. Those variables are extended with rows containing default values.
my_table = 1×7 table
name window fs x y z mag _________ ______ __ _ _ _ ___ <missing> 1 4 0 0 0 0 0

更多回答（2 个）

Walter Roberson
Walter Roberson 2021-7-11
编辑：Walter Roberson 2021-7-11
You cannot do that using that construction technique.
https://www.mathworks.com/matlabcentral/answers/867193-assigning-nested-tables-inside-a-parfor-loop#answer_735323
See also my answer there.
Sulaymon Eshkabilov
It is better to create a zero matrix and then assign a table variable, e.g.:
Nrows=10; Ncols=8;
A = zeros(10, 8);
my_table = array2table(A, 'VariableNames', {'name', 'win1', 'win2', 'fs','x', 'y', 'z', 'mag'});
%% Assign the values
my_table.win1(1)=1;
my_table.win2(1)=4;
%% Make a new column (var named "window")
my_table.window=[my_table.win1, my_table.win2];
my_table.win1=[];
my_table.win2=[];

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