How to divide a signal to a function?

Question

Fatemeh Sharafi 2021-7-13

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/877248-how-to-divide-a-signal-to-a-function

评论： Fatemeh Sharafi 2021-7-13

Hi dear friends. I have a nonstationary signal and I want to divide it to a 4-order polynomial function. but the result doesn't seem correct:

I simply do it like :

w= signal./function

Here's the signal plot:

this is the function:

and the result (when I divide them) is this:

I don't know what that big peak is? Logcally it shouldn't seem like this and should be like a stationary signal

I would be so garteful if you guide me

0 个评论
显示 -2更早的评论隐藏 -2更早的评论

请先登录，再进行评论。

请先登录，再回答此问题。

Answer 1

Chunru 2021-7-13

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/877248-how-to-divide-a-signal-to-a-function#answer_745478

The "function" has a value close to 0 and thus division by 0 (or small value) results in the big peak.

3 个评论
显示 1更早的评论隐藏 1更早的评论

Chunru 2021-7-13

在 MATLAB Online 中打开

It depends on what you want to do, which you did not explain clearly. Anyway you should always avoid the division by zero. You many consider the following:

w= signal./ (f+0.5); % don't use function as variable name

Fatemeh Sharafi 2021-7-13

this function was obtained from curve fitting the 4th-order polynomial func to a non-statinary signal. Then I used the fit function to convert the nonstationary signal to stationary by divide them.

thanks by the way. Your help was perfect

请先登录，再进行评论。