for recursive formula index value
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I was coding the formual
The summation runs for l=0 to k
I write the following code :
syms x
syms a
T=zeros(1,10,'sym')
T(1)=a;
T(2)=0;
for k=2:10
if k==2
A=1
for i=1:k
T(k+2-i)=(-A-(k+2-i)*(k+1-i)*T(k+2-i))/((k-i+1)*(k-i+2));
end
else
A=0
end
end
disp(T)
Here my code is: Now I have asumr T(2) as 0 but when it display T it is showing 2.
回答（1 个）
Prince Kumar
2021-8-13
From my understanding T(2) is getting updated after running the program but you have assumed T(2) to be 2 at the staring of the program.This might be because in this line
for i=1:k
T(k+2-i)=(-A-(k+2-i)*(k+1-i)*T(k+2-i))/((k-i+1)*(k-i+2));
end
you are changing T(2) for i=2 and k=2.
Hence T(2) is getting updated from 0 to some other value.
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2021-7-13
2021-8-13
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