Inverting an equation.
显示 更早的评论
Hello everyone,
I've got the following formula, with a/a* and gamma known.
a/a*=(1/m)*(2/(gamma+1))*(1+((gamma-1)/2)*m^2)^((gamma+1)/(2*(gamma-1)))
What I need are the corresponding Machnumbers M. I would like to write it in a script. Can anyone help me with this problem?
Many thanks!
回答（1 个）
Walter Roberson
2011-6-4
0 个投票
This does not have a simple solution. It involves finding the roots of an expression with one component of the root being taken to the power of 1/2 * (gamma+1)/(gamma-1) . Due to the form of the expression, you cannot simply use logs to transform the expression.
Effectively you will have to use fzero() to find the answer.
类别
在 帮助中心 和 File Exchange 中查找有关 Switches and Breakers 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
Translated by 
