Find minimum and maximum from same matrix

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Ajit Bashyal
Ajit Bashyal 2021-7-14
评论： Ajit Bashyal 2021-7-16
I have a matrix of 1181*101 that is a Power of an electric vehicle. It has positive, negative and zeros. Now I need to choose minimum of positive from total matrix and maximum of negative from the same total matrix. How can I do it?
Example
i=1181, j=101
% Power =[1181*101] containing both positive, negative and zeros.
% Now,
if Power(i, j) >= 0
[P, index] = min(Power, [], 2);
else
%(i.e. Power(i,j)<0)
[P, index] = max(Power, [], 2);
But every time, either it is taking only minimum or only maximum at a time. I tried changing negative terms to zero for minimum and positive terms to zero for maximum, but it still did not work. Please help me.
I can email to you if you require more details like code and variables.
  3 个评论
显示 1更早的评论
Image Analyst
Image Analyst 2021-7-14
You can attach the variables right here. Why not make it easy for people to help you, not hard? Why make us go through an extra step to get your matrix when you could have just attached it in a .mat file right here when you originally posted?
Ajit Bashyal
Ajit Bashyal 2021-7-16
This is the attached file. One more question to Jan, can't i write it in the same variable name like minPositive and maxNegative making a same name as minmax or something like that? And yes I need to neglect the zero because it doesnot have any use.

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采纳的回答

Jan
Jan 2021-7-14
I guess, that zeros values should be ignored. Then:
tmpPower = Power;
tmpPower(tmpPower <= 0) = Inf;
[minPositive, index1] = min(tmpPower, [], 2);
tmpPower = Power;
tmpPower(tmpPower > 0) = -Inf;
[maxNegative, index2] = max(tmpPower, [], 2);

更多回答（1 个）

David Hill
David Hill 2021-7-14
m=yourMatrix;
m(m<=0)=inf;
Min=min(m,[],'all');
m=yourMatrix;
m(m>=0)=0;
Max=-max(abs(m),[],'all');

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