Matrix with different order

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Chetan Fadnis 2021-7-14

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https://ww2.mathworks.cn/matlabcentral/answers/878783-matrix-with-different-order

评论： Chetan Fadnis 2021-7-14

I want to use 10*1 matrix for N=10, now as I keep changing N =20,30,40,50, matrix order must also change like, 20*1,30*1,40*1,50*1... using rand(N,1) I can produce required array. My problem is I am using a for loop, N=10:10:50 And I want to use matrix of order N*1 defined Outside of this loop. Kindly help how to write the code.

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DGM 2021-7-14

编辑：DGM 2021-7-14

If your vector needs to be of variable length, based on the state of the loop, why can't you do it in the loop? You'd need to precalculate all the vectors otherwise. You could store them in a cell array, but why set up one loop to build an array of variable length vectors just to avoid generating them at the time of use in another loop?

Depending on your needs, you may be able to calculate one oversize vector and then generate the shorter vectors by sampling from it, but I don't see how that's going to be easier than just doing it in the loop.

Chetan Fadnis 2021-7-14