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Find the index of the element of a cell array which has the maximum size

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AP
AP 2011-6-4
编辑： Jan 2017-10-27
I have a cell array (B) which has elements having two columns and different number of rows. I want to find the element which has the largest number of rows. I wrote the following code which seems to me non-professional. Is there a better way to do that?
max_index=0;
max_size=0;
for i=1:numel(B)
if max_size<size(B{i},1)
max_size=size(B{i},1);
max_index=i;
end
end
Thanks.

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采纳的回答

Jan
Jan 2011-6-4
[max_size, max_index] = max(cellfun('size', B, 1))
  2 个评论
Jan
Jan 2017-10-27
编辑：Jan 2017-10-27
@huahua:
siz = cellfun('size', B, 1);
[~, idx] = max(siz);
siz(idx) = -Inf;
[size2, index2] = max(siz);
This is cheaper than sorting.

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更多回答（1 个）

Jos (10584)
Jos (10584) 2017-10-26
NrowsB = cellfun('size',B,1) ;
[~, ri] = sort(NrowsB)
ri(k) % index of B with the k-th most number of rows

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