Reading Arrow Key Input
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What I'm basically trying to do is control a robot by using the arrow keys on the keyboard. I'm already familiar with outputting commands via MATLAB my main problem is how to read what arrow keys I'm pressing. Ultimately I would like to press an arrow button and have it displayed on the command window.
I came across this bit of code online. It works great but I need the keystrokes to be store in a variable (possibly as a number instead of a string) so I can output it. There may be a simple solution but since I don't really understand the code my attempt to edit it didn't work.
h_fig = figure;
set(h_fig,'KeyPressFcn',@(h_obj,evt) disp(evt.Key));
Thank You
Sayyid Khan
采纳的回答
Matt Fig
2011-6-4
Here is an example of how to use the arrow keys in the keypressfcn.
function [] = move_fig()
% move figure with arrow keys.
S.fh = figure('units','pixels',...
'position',[500 500 200 260],...
'menubar','none',...
'name','move_fig',...
'numbertitle','off',...
'resize','off',...
'keypressfcn',@fh_kpfcn);
S.tx = uicontrol('style','text',...
'units','pixels',...
'position',[60 120 80 20],...
'fontweight','bold');
guidata(S.fh,S)
function [] = fh_kpfcn(H,E)
% Figure keypressfcn
S = guidata(H);
P = get(S.fh,'position');
set(S.tx,'string',E.Key)
switch E.Key
case 'rightarrow'
set(S.fh,'pos',P+[5 0 0 0])
case 'leftarrow'
set(S.fh,'pos',P+[-5 0 0 0])
case 'uparrow'
set(S.fh,'pos',P+[0 5 0 0])
case 'downarrow'
set(S.fh,'pos',P+[0 -5 0 0])
otherwise
end
%
%
%
%
EDIT
% This assigns the string value of the key to a in the base workspace.
set(h_fig,'KeyPressFcn',@(H,E) assignin('base','a',E.Key));
2 个评论
Matt Fig
2011-6-5
sayyid khan comments,
Thanks for the quick response. But is there a way I can use that original 2 lines of code and just have it save to a variable.
For example
Press right arrow > a = 'right arrow'; Press left arrow > a = 'left arrow'.
If it could give me the variable in terms of the ascii code that would be perfect.
Thank you
Sayyid Khan
Matt Fig
2011-6-5
See my edit above.
Put comments on particular answers in the comments section, not as new 'answers'....
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2011-6-4
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