How to convert a cell array to a compatible matrix?

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Nandha Kumar
Nandha Kumar 2021-7-16
评论： Nandha Kumar 2021-7-17
I have a cell array which is filled with matrices of varying size, could you help me to convert it to matrix with filling zeros at in between columns,
in this case the matrix size is ought ot be 41x 41 of double type.

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采纳的回答

Jan
Jan 2021-7-16
编辑：Jan 2021-7-16
Ran in:
CC = {rand(9,9), rand(5,4), rand(5,4), rand(6,4), rand(6,4), rand(8,4), rand(8,4), rand(9,4), rand(9, 4); ...
rand(4,5), rand(4,4), [], [], [], [], [], [], []; ...
[], [], rand(4,4), [], [], [], [], [], []; ...
rand(4,6), [], [], rand(4,4), [], [], [], [], []; ...
[], [], [], [], rand(4,4), [], [], [], []; ...
rand(4,6), [], [], [], [], rand(4,4), [], [], []; ...
[], [], [], [], [], [], rand(4,4), [], []; ...
rand(4,6), [], [], [], [], [], [], rand(4,4), []; ...
[], [], [], [], [], [], [], [], rand(4,4)};
C = CC;
S1 = cellfun('size', C, 1);
maxS1 = max(S1, [], 2);
S2 = cellfun('size', C, 2);
maxS2 = max(S2, [], 1);
for i2 = 1:size(C, 2)
for i1 = 1:size(C, 1)
X = C{i1, i2};
if size(X, 1) < maxS1(i1) || size(X, 2) < maxS2(i2)
X(maxS1(i1), maxS2(i2)) = 0;
C{i1, i2} = X;
end
end
end
Result = cell2mat(C);
Cheaper:
C = CC;
S1 = cellfun('size', C, 1);
maxS1 = max(S1, [], 2);
S2 = cellfun('size', C, 2);
maxS2 = max(S2, [], 1);
Result2 = zeros(sum(maxS1), sum(maxS2));
c1 = 1;
for i1 = 1:size(C, 1)
c2 = 1;
for i2 = 1:size(C, 2)
X = C{i1, i2};
Result2(c1:c1 + size(X,1) - 1, c2:c2 + size(X,2) - 1) = X;
c2 = c2 + maxS2(i2);
end
c1 = c1 + maxS1(i1);
end
isequal(Result, Result2)
ans = logical
1
It took some tome to create some test data as input. Please care for providing some code, which creates your input data, to make answering as easy as possible.
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