Calculate mean from a cell array.

Question

Rajvi Amle 2021-7-16

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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/880043-calculate-mean-from-a-cell-array

编辑： Rik 2021-7-18

Sum_col.mat

I am trying to calculate the mean from 1x10 cell array where the array contains matrices of 138x1 dimensions. But the dimensions of all 10 arrays are not the same. So is it possible to calculate mean out of all together the cell arrays having different dimensions? Here I am attaching the file Sum_col.mat from which I want to calculate the mean.

Any help would be really appreciated. Thank you in advance.

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Answer 1

Rik 2021-7-16

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https://ww2.mathworks.cn/matlabcentral/answers/880043-calculate-mean-from-a-cell-array#answer_748213

在 MATLAB Online 中打开

Two options of what you could mean:

%load your data first
websave('data.mat','https://www.mathworks.com/matlabcentral/answers/uploaded_files/686468/Sum_col.mat');
Sum_col=load('data.mat');Sum_col=Sum_col.Sum_col
Sum_col = 1×10 cell array
    {135×1 double}    {138×1 double}    {136×1 double}    {136×1 double}    {133×1 double}    {136×1 double}    {136×1 double}    {135×1 double}    {137×1 double}    {136×1 double}
%mean of each cell (returning a 1x10 array)
cellfun(@mean,Sum_col)
ans = 1×10
    0.0785    0.0792    0.0773    0.0814    0.0712    0.0781    0.0716    0.0701    0.0790    0.0763
%mean of every element (returning a 138x1 array)
tmp=Sum_col;max_sz=max(cellfun('prodofsize',tmp));
for n=find(cellfun('prodofsize',tmp)<max_sz)
    tmp{n}((end+1):max_sz)=NaN; % fill extra entries with NaN
end
mean(cell2mat(tmp),2,'omitnan')
ans = 138×1
         0
    0.0004
    0.0007
    0.0011
    0.0029
    0.0046
    0.0064
    0.0080
    0.0109
    0.0137

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Rajvi Amle 2021-7-17

在 MATLAB Online 中打开

@Rik Thank you so much for your response and help. Further based on this mean calculation, I tried to calculate standard deviaion and confidence interval as:

%mean of every element (returning a 138x1 array)
tmp=Sum_col;max_sz=max(cellfun('prodofsize',tmp));
for n=find(cellfun('prodofsize',tmp)<max_sz)
    tmp{n}((end+1):max_sz)=NaN; % fill extra entries with NaN
end
mean(cell2mat(tmp),2,'omitnan')
std=col_mean/size(tmp,2);  % standard deviation
CI95 = mean + 1.96.*(std/sqrt(length(tmp)))   %confidence interval

So i just wanted to confirm that in standard deviation calculation, I should take size of tmp as 'size(tmp,2)' or size(max_sz,2)? Could you please help me giving any suggestions?