could anyone help me how to solve the error in the following code

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jaah navi 2021-7-16

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评论： jaah navi 2021-7-17

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I am having cell array

B=10x1 cell

which contains

10x4 double
10x4 double
10x4 double
10x4 double
10x4 double
10x4 double
10x4 double
10x4 double
10x4 double
10x4 double

I used the following code to convert it

A=cell(size(B));
for i=1:numel(B)
    A{i}=splitapply(@(x){x}, 1:numel(B{i}) ,B{i});
    
    disp("YTest{" +i+ "}:"), B{i}
    for j=1:numel(A{i})
    disp("A{" +i+ "}{"+j+"}:"), A{i}{j}
    end
    disp ' '
end

But it results in error. Could anyone please help me to overcome it.

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jessupj 2021-7-16

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what is the error, exactly?

what is the line

splitapply( @(x) {x}, 1:numel(B{i}) ,B{i} )

supposed to do? it looks like that's where is problem to me

jaah navi 2021-7-16

Error using splitapply

Group numbers must be a vector of positive integers, and cannot be a sparse vector.

Error in line 3

A{i}=splitapply(@(x){x}, 1:numel(B{i}) ,B{i});

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回答（1 个）

Walter Roberson 2021-7-16

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The last parameter to splitapply must be a vector of positive integers, one for each row of input, with the number indicating which group the row belongs to.

It is not clear that your B values are integers. It is clear that B{i} is not a vector.

Perhaps you accidentally exchanged the second and third parameters.

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Walter Roberson 2021-7-16

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Unfortunately, you did not explain what output you want.

rng(12345)
B{1} = randi(9, 3, 4);
B{2} = randi(9, 3, 4);
celldisp(B)
 
B{1} =
 
     9     2     9     6
     3     6     6     7
     2     6     7     9

 
 
B{2} =
 
     1     6     9     7
     1     8     7     5
     3     8     6     3

 

What exact output would you want for the above?

jaah navi 2021-7-17