could anyone help me how to compute the mean square error between two cell.

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jaah navi
jaah navi 2021-7-17
评论： jaah navi 2021-7-19
I am having two cell A and B in the attached data.mat.
I want to compute the mean square error between A and B in data.mat.
Could anyone please help me on this.
  2 个评论
Yazan
Yazan 2021-7-17
How are you defining the MSE for your data? Each cell of A and B is a N-by-2 vector.
jaah navi
jaah navi 2021-7-17
Here, both A and B has the same N-by-2 vector, for example
A{1,1}
1 2
1 1
1 1
1 1
1 2
1 1
1 2
1 2
1 2
1 2
B{1,1}
1 1
1 2
1 1
1 1
1 1
1 1
1 2
1 2
1 2
1 1
So first column of A needs to get subtracted with first column of B denoted by C and second column of A needs to get subtracted with second column of B denoted by D. Then I need to find the difference between C and D, square it and add all the rows and divide it by the 10.

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采纳的回答

Walter Roberson
Walter Roberson 2021-7-17
cellfun(@(a,b) sqrt(sum(a(:)-b(:)).^2))
You had the wrong definition of mean square error.
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jaah navi
jaah navi 2021-7-18
i am getting error stating Undefined operator '-' for input arguments of type 'cell'.
Walter Roberson
Walter Roberson 2021-7-18
Please show the output of the following:
cellfun(@(a)string(class(a)), A)
cellfun(@(a)string(class(a)), B)
I suspect your A and B are not cell array of double like you indicate here. Judging by some of your other posts, I suspect that you have a mix, that some of the entries are double and others are cell.

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jaah navi
jaah navi 2021-7-18
Anyhow i managed to get the partial output as required using the following commands for my data.mat as attached.
C=cellfun(@minus,A,B,'UniformOutput',false);
D=cellfun(@(x) sum((x(:,1)-x(:,2)).^2)/10,C,'UniformOutput',false)
Now I want to sum up all the rows of D and divide it by 5.
Could you please help me on this.
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