Averaging values in rank orderings with repeats

2 次查看(过去 30 天)
I'm wondering if there is a straightforward way for me to complete the following task.
Suppose u=[1,3,2,2,4,7,2,5] and I wish to create a vector of rank orderings that accounts for the fact that the three 2's are tied for ranks 2, 3, and 4 by using the average of these three ranks, (2+3+4)/3=3 in each corresponding entry.
More specifically, I want the rank ordering vector to be [1,5,3,3,6,8,3,7]. Notice how there is no 2 and no 4.

采纳的回答

Kelly Kearney
Kelly Kearney 2013-9-24
The accumarray function should do what you want:
u = [1,3,2,2,4,7,2,5];
nu = length(u);
rank = (1:nu)';
ravg = accumarray(sort(u'), rank, [nu 1], @mean);
ravg(u)
  2 个评论
Paul Fishback
Paul Fishback 2013-9-24
Thanks! Not only for such a quick answer, but also for introducing me to the accumarray command.
Paul Fishback
Paul Fishback 2013-9-24
The first argument for accumarray has to be a vector of positive integers. What if this were not the case for my vector u?

请先登录,再进行评论。

更多回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Time Series 的更多信息

产品

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by