How to chose the correct line style?

Question

Louise Wilson 2021-7-21

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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/882773-how-to-chose-the-correct-line-style

回答： Jonas 2021-7-22

I have created the attached plot. I have a large dataset with multiple entries, each representing different moving objects. I want to draw a line plotting the movement of each unique object, per day. This works, but the display is different depending on whether I use scatter or plot. If I use plot, I get the type of line I would like, where the lines are connected, but using scatter, solitary points (that aren't moving) are missed from the plot. How do I choose a line style which allows me to show both the solitary points and connect those points that are related?

For example, I see that I could just plot one of each line style over the top of each other, but then I lose the unique colours attached to each set of data points.

subplot(5,1,1)
unique_MMSI=unique(gps_data.cpa3);
for i=1:height(unique_MMSI)
    
    MMSI=unique_MMSI(i);
    
    S=gps_data.cpa3==MMSI;
    gps_sub=gps_data(S,:);
    
    [N,edges,bin] = histcounts(datetime(gps_sub.cpa1,'ConvertFrom','datenum'),'BinMethod','day');
    
    bin_num=unique(bin);
    bin_num=bin_num';
    
    for ii=1:width(bin_num)
        
        bin_on=bin_num(ii);
        
        [lia,loc]=ismember(bin,bin_on);
        
        gps_plot=gps_sub(lia,:);
        gps_plot.DateTime=datetime(gps_plot.cpa1,'ConvertFrom','datenum');
        
        plot(gps_plot.DateTime,gps_plot.vessel_CPAs)
        hold on
    end
    hold on
end
ylim([0 5])
starttime=datetime(2020,1,1,0,0,0);
endtime=datetime(2020,6,7,0,0,0);
xlim([starttime, endtime]);
xticks(starttime:days(7):endtime); %change range of x-axis using times from .wav
xlim([starttime, endtime]);
xtickangle(0);

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Louise Wilson 2021-7-21

Thanks Jonas! That solved it. I didn't realise, thank you!

Jonas 2021-7-22

great to hear it was what you were searching for. i will post the comment as answer below, you can then accept it and then this forum has one question less to be solved

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