清空筛选条件
清空筛选条件

Replacing 0 with NaN by indexing into a matrix

4 次查看（过去 30 天）
Jenny
Jenny 2013-9-26
编辑： Azzi Abdelmalek 2013-9-26
I have a data matrix called 'data' of 84761 x 11. (a small selection of the data is attached).
I am able to allocate column variable into arrays e.g. column 10 = WindDirec with DD1 = data(:,10).
I can then replaces the 0 values with NaN by: DD1(DD1==0)=NaN.
Is there a way to do this without first assigning column variables to arrays? I would like to index into the matrix 'data' and replaces all 0 values in column 10 with NaNs.
data(data(:,10)==0)=NaN; replaces the values in the first column with NaN, given by the index provided by where column 10 = 0;
How do I index to column 10 to then replace the 0's with NaNs?
Thank you Jenny

请先登录，再回答此问题。

采纳的回答

Azzi Abdelmalek
Azzi Abdelmalek 2013-9-26
编辑：Azzi Abdelmalek 2013-9-26
data(data(:,10)==0,10)=nan

更多回答（0 个）

类别

在 Help Center 和 File Exchange 中查找有关 Matrix Indexing 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by