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OK, this is true ?multiplying scalar 'k' by matrix 'v'
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such as
Z = zeros(size(W1));
kernel = [Z, W1, Z; W3, Z, W4; Z, W2, Z];
filtered = conv2(vk, kernel, 'same');
vk = (1-w)*vk + filtered./W;
where 'k' is iteration
'v' is matrix
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