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OK, this is true ?multiplying scalar 'k' by matrix 'v'

1 次查看(过去 30 天)
such as
Z = zeros(size(W1));
kernel = [Z, W1, Z; W3, Z, W4; Z, W2, Z];
filtered = conv2(vk, kernel, 'same');
vk = (1-w)*vk + filtered./W;
where 'k' is iteration
'v' is matrix
  2 个评论
Jan
Jan 2013-9-28
编辑:Jan 2013-9-28
How could we decide if "it is true"? It depends, on what you are exactly searching for.I do not see "k" in the code, so what does it mean, that it is a "iteration"? I cannot find "V" also.
Mary Jon
Mary Jon 2013-9-28
vk that not 'function' or variables;
'k' is iteration counter, 'v' is matrix

回答(1 个)

Image Analyst
Image Analyst 2013-9-28
I don't see v * k anywhere in your code, so I guess the answer is no.
  1 个评论
Mary Jon
Mary Jon 2013-9-28
I get this code from you(matlab answers) when asked you to write my equation ,where I told you 'k' iteration counter,'v' matrix!
yor answer was,
Z = zeros(size(W1));
kernel = [Z, W1, Z; W3, Z, W4; Z, W2, Z];
filtered = conv2(vk, kernel, 'same');
vk = (1-w)*vk + filtered./W;
why you write 'v' and 'k'as (vk)?

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