Geotiffread & getting latlon info

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Hello,
I am using EO-1 Hyperion data (hyperspectral) as a geotiff image data of Agatti Islands, Lakshadweep, India. I used geotiffread to read the image data.. using [img, RfrncMtrx, BndgBx]=geotiffread(phileName{:}); When I want to convert from the row/col to lat/lon by using pix2latlon, I get the numbers in map-scale. (Actually the values in the reference matrix are also huge!!!???). The BndgBx=[179100, 1155270; 206430, 1244100]..
Kindly let me know where I am going wrong?
Cheers
Raghu
  3 个评论
Hyunglok Kim
Hyunglok Kim 2017-10-19
Luka's answer is the best.
Nirajan Luintel
Nirajan Luintel 2018-4-4
I used to calculate from boundary box. Its a lot easier. Thanks a lot

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采纳的回答

Kelly Luetkemeyer
编辑:Kelly Luetkemeyer 2022-6-21
Here is updated code to adress this request using recent (R2022a) features in Mapping Toolbox:
%% Read image file using readgeoraster
fname = "boston.tif";
[A,R] = readgeoraster(fname);
%% Create grid of X,Y values
[x,y] = worldGrid(R);
%% Convert grid of X,Y values to latitude/longitude
[lat,lon] = projinv(R.ProjectedCRS,x,y);
%% Plot latitude/longitude min/max on geographic axes to confirm
[latlim,lonlim] = geoquadline(lat,lon);
figure
geoplot(latlim([1 2 2 1 1]),lonlim([1,1,2,2,1]),"r","LineWidth",2)
geobasemap satellite
title("geographic axes")
figure
mapshow(A,R)
title("boston.tif")
********************************
Hi Raghu,
As background information, the coordinates of your image are in a projected coordinate system rather than a geographic coordinate system. You can use the function GEOTIFFINFO to return the information structure.
You will see the 'ModelType' field set to 'ModelTypeProjected'; therefore, the RefMatrix is also referenced to map coordinates.
Beginning in R2011a, you will also see a new field, SpatialRef, which in this case will contain a spatialref.MapRasterReference object.
If you want to find the geographic coordinates from the map coordinates, then you need to use the function PROJINV to unproject the coordinates to latitude and longitude.
Here is how you would find the latitude and longitude values for the center of the first pixel in boston.tif:
info = geotiffinfo('boston.tif');
[x,y] = pix2map(info.RefMatrix, 1, 1);
[lat,lon] = projinv(info, x,y)
Beginning in R2011a, you can use:
[x,y] = pix2map(info.SpatialRef, 1, 1)
or
R = info.SpatialRef;
[x,y] = R.intrinsicToWorld(1,1);
followed by:
[lat,lon] = projinv(info, x,y);
I hope this help you.
-Kelly
  5 个评论
TT1981
TT1981 2016-9-1
I know this is a really old post, but since I was struggling with the same as OP and there are not many posts online related to this, I would like to include a solution to shorten computing time:
[AY, AX]= size (data);
lon = zeros(size(data));
lat = zeros(size(data));
x = zeros(1, AX);
y = zeros(1, AY);
height = info.Height; % Integer indicating the height of the image in pixels
width = info.Width; % Integer indicating the width of the image in pixels
[rows,cols] = meshgrid(1:height,1:width);
% Getting the latitude and longitude of the points
[x,y] = pix2map(info.RefMatrix, rows, cols);
[lat,lon] = projinv(info, y,x);
This way you do not need to loop through all the points.
Tom Bell
Tom Bell 2019-2-24
You made my day! Thank you!

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更多回答(3 个)

Reema Alhassan
Reema Alhassan 2018-6-4
hello, when I'm using projinv(info, y,x); function I'm getting an error says the GeoTIFF structure PROJ can't be used with the functions PROJFWD or PROJINV if you could help me please ..
thank you
  7 个评论
Sophia Barth
Sophia Barth 2020-8-21
This is the code i used to export the image:
If you have an account for Google Earth Engine it should work when you click on the link. If the link somehow doesnt work this is the code:
/**
* Function to mask clouds using the Sentinel-2 QA band
* @param {ee.Image} image Sentinel-2 image
* @return {ee.Image} cloud masked Sentinel-2 image
*/
function maskS2clouds(image) {
var qa = image.select('QA60');
// Bits 10 and 11 are clouds and cirrus, respectively.
var cloudBitMask = 1 << 10;
var cirrusBitMask = 1 << 11;
// Both flags should be set to zero, indicating clear conditions.
var mask = qa.bitwiseAnd(cloudBitMask).eq(0)
.and(qa.bitwiseAnd(cirrusBitMask).eq(0));
return image.updateMask(mask).divide(10000);
}
//Filter images
var dataset = ee.ImageCollection('COPERNICUS/S2')
.filterBounds(geometry5)
//.filterDate('2016-07-23','2016-07-27')
.filterDate('2020-07-01','2020-07-30')
.filterMetadata('CLOUDY_PIXEL_PERCENTAGE','less_than',20)
.map(maskS2clouds)
.median()
.select(['B12','B8','B4'])
//visualization parameter
var SWIRVis = {
min: 0.0,
max: 0.3,
bands: ['B12', 'B8', 'B4'],
};
//output image, add to map
var final_image = dataset.clip(geometry5)
Map.addLayer(final_image,SWIRVis,'Image2016-06');
//Map.addLayer(final_image,VisParam,'image201607_1_fire');
//Export the image, specifying scale and region
Export.image.toDrive({
image: final_image,
description: 'image202007_swir_small',
scale: 20,
crs: 'EPSG:3857',
region: geometry5
});
I hope that helps, thanks again!
Sophia Barth
Sophia Barth 2020-8-21
As a next step I dowloaded the image from Googe Drive and used the follwoing code as you suggested:
info = geotiffinfo('image202007_swir_small.tif');
[x,y] = pix2map(info.RefMatrix, 1, 1);
[lat,lon] = projinv(info, x,y)

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Ran Zask
Ran Zask 2018-3-24
I think it should be [lat,lon] = projinv(info, x,y);
  1 个评论
Qishun Ran
Qishun Ran 2019-6-19
I think you are right, it should be [lat,lon] = projinv(info, x,y); and
it should be [rows,cols] = meshgrid(1:width,1:height);

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Andres Rey Sanchez
Andres Rey Sanchez 2021-7-26
Some corrections are needed to the answers above. To get the correct matrices of coordinates (lat, lon) from your geotiff the code should be:
info = geotiffinfo('boston.tif');
height = info.Height; % Integer indicating the height of the image in pixels
width = info.Width; % Integer indicating the width of the image in pixels
[cols,rows] = meshgrid(1:width,1:height);
[x,y] = pix2map(info.RefMatrix, rows, cols);
[lat,lon] = projinv(info, x,y);

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