How to generate a matrix of random decimal values from -1 to 1?

14 次查看(过去 30 天)
I want to generate a 8x10 matrix full of random decimal values from -1 to 1, each with EXACTLY 6 decimal places (i.e 0.523483, -0.932401, etc.).
I know that this code generates values with 7 decimal places (not sure how to get it to 6). But, I don't know how to automatically generate a matrix full of values like these (without using a for loop). Any ideas? thanks!
format long
disp(single(rand(3)))
  1 个评论
Rik
Rik 2021-7-27
Note that single doesn't have normal decimal places, as it is a floating point number. They take this shape:
(-1)^sign*2^(exponent-127)x1.fraction
%double has -1023 instead of -127
What you want is to round, which might affect the distribution of your values in subbtle and unintuitive ways.

请先登录,再进行评论。

回答(1 个)

KSSV
KSSV 2021-7-27
编辑:KSSV 2021-7-27
format long
A = single(rand(3)) ;
fmt = [repmat(' %0.6f',1,3),'\n'];
fprintf(fmt,A)
0.753020 0.794493 0.884238 0.019086 0.490358 0.960622 0.517914 0.845987 0.772295

类别

Help CenterFile Exchange 中查找有关 Creating and Concatenating Matrices 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by