Solving Matrix Index Problem
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is anyone here know how to solve matrix index problem in matlab?? For example the following problem :
You have a matrix for which each row is a person and the column represent the number of quarters, nickels, dimes, and pennies. What is the raw index of the person with the most money?
Note for those unfamiliar with American coins ; quarter = $ 0.25, dime = $ 0.10, nickel = $ 0.05, penny = $0.01
Example :
Input a = [1 0 0 0 ; 0 1 0 0] output b = 1
since the first person will have $ 0.25 and the second person will have only $0.05
Thanks you, i need the answer..
采纳的回答
Azzi Abdelmalek
2013-9-30
c=[0.25 0.1 0.05 0.01]
a = [1 0 0 0 ; 0 1 0 0]
[max_money,b]=max(sum(bsxfun(@times,c,a),2))
更多回答（4 个）
Rahul Sharma
2020-2-8
clear all
clc
a=randi(4,3,4)
k=[0.25 0.10 0.05 0.01];
for j=1:4
for i=1:3
a(i,j)=k(j)*a(i,j)
end
end
b=max(sum(a'))
disp(b)
Rahul Sharma
2020-2-8
a=randi(4,3,4)
a(:,1)=0.25*a(:,1);
a(:,2)=0.10*a(:,2);
a(:,3)=0.05*a(:,3);
a(:,4)=0.01*a(:,4);
disp(a)
b = max(sum(a'));
disp(b)
Mohana Segaran
2023-7-19
0 个投票
a = [1 0 0 0; 0 1 0 0; 1 1 1 0];
b = [0.25 0.1 0.05 0.01; 0.25 0.1 0.05 0.01; 0.25 0.1 0.05 0.01];
x = dot(a,b,2);
[y z]= max(x);
z
The simple and efficient approach is to use MTIMES:
M = [1,0,0,0;0,1,0,0;0,2,1,1] % any number of rows
V = [0.25;0.1;0.05;0.01]; % one column
[~,X] = max(M*V)
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