Grouping vectors into groups of 3 by attribute
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Three groups are given, each with eight
-vectors:
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/697114/image.png)
V1=
-0.0953681318008175 0.858850259468781 0.465327737835860
-0.743367248943597 0.315573550722436 -0.557734004373653
0.683550749866093 -0.246647785705382 0.659675673733952
-0.181058614839515 -0.767007049361869 -0.584950182984675
0.118761748181243 0.743380411572561 0.629706251526340
-0.721912423469330 0.520402704143404 -0.413850493189363
0.684870513276088 -0.444565219875274 0.544575887892960
0.00541628034354009 -0.874348540602108 -0.445795968809064
V2=
0.288328864090772 0.663613522812372 -0.690270583470916
-0.0661655475859850 0.714486376794470 0.696506466316257
0.0659856355945583 -0.714480201575689 -0.696529868264201
-0.290257865507787 -0.355082937133591 0.888626130158261
0.293720151348812 0.453108073152230 -0.841671828368103
0.0218190503132586 0.884590829792312 0.465846447687839
-0.0107163145532371 -0.867045341360451 -0.498103861217854
-0.293858044300728 -0.555374924488560 0.777943483153936
V3=
-0.983704829430046 0.127754733568269 -0.126193025298098
0.569942911640406 0.507765297260453 -0.645957137429290
-0.600866408147646 -0.493858673852356 0.628477774346492
0.913781057203716 -0.270305866504114 0.303084247456218
-0.902987180751040 0.284301799787109 -0.322036925000972
0.766156223036288 0.391842259005210 -0.509298958360849
-0.772797513782289 -0.387356431991189 0.502653101367087
0.984595406214300 -0.125219791950337 0.121708803266623
Task:
it is necessary to take a vector from each group and compose a basis in such a way that the angles between the corresponding pairs of vectors (i.e.
) are the same or differ insignificantly, i.e. the result should be 8 bases that meet these requirements.
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/697244/image.png)
How to do it in MATLAB?
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