Replacing function variables with a vector before taking a gradient

2021 7 30
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更新时间：2021 7 31
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I have a symbolic function:
A = 1/((C1*C2*R1*R2*w^2 - 1)^2 + w^2*(C2*R1 + C2*R2)^2)^(1/2)
I would like to replace C1, C2, R1, R2 symbolic variables with an x vector where C1 = C1_0*x(1); C2 = C2_0*x(2); R1 = R1_0*x(3); R2 = R2_0*x(4); and take a gradient of A by x. Whatever I tried failed to produce the result I am seeking.

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darova
darova 2021-7-30
To calcualte gradient/derivative you need at least two points for C1,C2 ...
Do you have them?
Valeri Aronov
Valeri Aronov 2021-7-30
I do it symbolically, if I got your question right.
Valeri Aronov
Valeri Aronov 2021-7-31
编辑：Valeri Aronov 2021-7-31
I have found a path (I did not know about str2sym() existence):
syms x1 x2 x3 x4 real
x=[x1,x2,x3,x4]
A = subs(A, C1, str2sym('x1*C1_0'))
A = subs(A, C2, str2sym('x2*C2_0'))
...
gradient(A, x)
It may do for me even ideally I would prefer the notation in my question text for x.
Now, can some one advise if I need to remove this question entirely.

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Walter Roberson
Walter Roberson 2021-7-31

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syms x1 x2 x3 x4 real
syms C1_0 C2_0
x=[x1,x2,x3,x4]
A = subs(A, [C1, C2, R1, R2], [C1_0, C2_0, R1_0, R2_0] .*x)
gradient(A, x)

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