MATLAB producing ans but wont upload variable, extremely strange behavior

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Robert Scott
Robert Scott 2021-7-31
评论： Image Analyst 2021-8-1
I am doing nothing special here but vectorizing an array
When i do something like the below code below matlab is going off, and producing an "ans" on the screen that has the correct values in it.
However, it is creating a completely empty variable called "test" despite the fact that i am setting that command to the variable test.
So i get the correct "ans" on the screen and an empty variable called test
What is going on here? I can click on "ans" in the workspace and see everything that should be there but test will be a variable of the same size but empty.
test = test1(1,1);test2(1,2)

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Image Analyst
Image Analyst 2021-7-31
编辑：Image Analyst 2021-7-31
Did you forget to enclose the vectors in brackets to form a matrix. See this:
test1 = rand(1,2);
test2 = rand(1,2);
test = test1(1,1); test2(1,2) % Two separate lines of code on the same line
test = [test1(1,1); test2(1,2)] % one line of code to stack the vectors on top of each other in a new matrix.
Did that produce a forehead-slapping moment?
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Robert Scott
Robert Scott 2021-7-31
not sure , but what i can tell you is that this is part of a function that is called nearly a million times
And going vectorized just save me 20 mS per call
Image Analyst
Image Analyst 2021-8-1
I was running it with join() to see how that differed from my two solutions and it appears that your input vectors area actually strings, not numerical, because join() only works with text.
So for completeness, I'm showing the two cases with different length vectors.
% Declare simple sample data.
test1 = [1,2,3,4];
test2 = [21,22,23,24,25,];
% For case 3, to use strrep, they must be strings, not numbers.
test1 = ["1","2","3","4"];
test2 = ["21","22","23","24", "25"];
% Case 2 : different lengths.
L1 = length(test1);
L2 = length(test2);
% Pad if necessary
if L1 < L2
t1 = [test1, zeros(1, abs(L2-L1))]
t2 = test2
elseif L2 < L1
t1 = test1
t2 = [test2, zeros(1, abs(L2-L1))]
else
t1 = test1;
t2 = test2;
end
output2 = reshape([t1;t2], 1, [])
% Case 3: join - requires strings, not numbers.
% Create an array of 8 elements
test = [test1(:).', test2(:).']
% Make it a single string with spaces between, not an array.
test = join(test)
% Remove all spaces.
test = strrep(test,' ','')
You see:
output2 =
1×10 string array
"1" "21" "2" "22" "3" "23" "4" "24" "0" "25"
test =
1×9 string array
"1" "2" "3" "4" "21" "22" "23" "24" "25"
test =
"1 2 3 4 21 22 23 24 25"
test =
"12342122232425"
If I had known that you were dealing with text in advance, and if I had known what you wanted in advance, it would have gone much quicker with less back and forth. Note that I used simple data for the example that was not proprietary or secret so I would not get into trouble with my company over IP issues because of patents I'm working on.

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