How to generate a binary matrix with unique rows (or) columns?

2021 8 1
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更新时间：2021 8 1
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n = 15; k = 10;
flag = 0;
for l=1:2^k
while(1)
temp = randi([0,1] , 1,n);
for m=1:l-1
if(codeword(m,:) == temp)
flag = 1;
end
end
if(flag ==0)
break;
end
end
codeword(l,:) = temp;
end
This is a very time complex code!!
Can anyone suggest any other way with which I can solve this problem?
Thanks.

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Jonas
Jonas 2021-8-1
编辑：Jonas 2021-8-1

i suggest you just write ascending numbers in binary format, then all rows or columns are unique. think about how many rows and digits you need. this way you could produce e.g.

0 0 0 0 0
0 0 0 0 1
0 0 0 1 0
...

the minimum width of your matrix is then given by nextpow2 of your number of rows, but if you need a broader matrix you are free to just use more bits

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Matt J
Matt J 2021-8-1
编辑：Matt J 2021-8-1
Ran in:

1 个投票

Ran in:
Something like this, perhaps?
n = 15; k = 10;
dec2bin( randperm(2^n,k) ) -'0'
ans = 10×15
1 0 1 0 1 0 0 1 1 1 1 0 0 0 0 1 0 0 1 1 0 0 0 1 0 0 1 0 1 0 1 1 0 1 1 1 0 0 1 1 1 0 1 0 0 0 1 1 1 1 0 0 0 0 1 0 1 1 0 0 0 1 0 0 1 1 0 0 0 1 0 0 0 1 1 0 0 0 0 0 0 1 1 0 0 0 1 1 0 1 1 1 0 1 1 1 1 0 1 1 1 0 0 1 1 0 1 1 1 1 1 0 0 1 1 1 1 1 0 1 1 1 0 1 1 0 1 1 0 0 1 1 1 1 1 0 0 1 1 0 1 1 0 1 1 1 1 0 0 1

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