function deal()

Yin
2011 6 6
1 个回答
回答已采纳
10 次查看（30 天）

0 个投票

I'm having trouble getting deal() to place one number in multiple places. My lines of code:
y1=[];
y2=[];
y3=[];
y={y1 y2 y3};
y=deal(5);
gives me the error: The right hand side of this assignment has too few values to satisfy the left hand side.

1 个评论
显示 -1更早的评论 隐藏 -1更早的评论

Yin
Yin 2011-6-6
er, sorry, the final line should read:
y{:}=deal(5);

请先登录，再进行评论。

请先登录，再回答此问题。

 采纳的回答

Matt Fig
Matt Fig 2011-6-6

0 个投票

y = cell(1,3); % dispense with the y1, y2, y3 stuff....
[y{:}] = deal(5)
or, without defining the variable first:
[Y{1:3}] = deal(5) % Y is not defined before this line..
But why use DEAL at all?
y = cell(1,3);
y(:) = {9}

1 个评论
显示 -1更早的评论 隐藏 -1更早的评论

Yin
Yin 2011-6-6
That's awesome, I can't read, lol.
I'm actually trying to figure out how to create a pointer-like structure where values can be dynamically changed without knowing all the variables that "point" to it.
Thanks for your help.

请先登录，再进行评论。

更多回答（0 个）

类别

在 帮助中心 和 File Exchange 中查找有关 Multinomial Distribution 的更多信息

产品

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by