Accessing a column of a structure array

Question

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I have multiple *.spc files in a folder which I want to access. I use the following code to get the file names:

folder_cal = uigetdir('','select calibration data folder');
Files_cal=dir(fullfile(folder_cal,'*.spc')) 

Files_cal is a structure array, when I enter Files_cal in command window I get:

Files_cal = 
  84×1 struct array with fields:
    name
    folder
    date
    bytes
    isdir
    datenum
    
    

I want to get the file names but when I use:

names=Files_cal.name

I get only one of the names (the first row). Can anyone tell me what am I doing wrong and how can I get all file names at the same time?

I can convert this stucture array to a cell format and solve the problem. But I want to learn how to handle structures.

Thank you in advance!

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Stephen23 2021-8-3

"Can anyone tell me what am I doing wrong and how can I get all file names at the same time?"

Answer 1

KSSV 2021-8-3

0 个投票

names = {Files_cal (:).name} ;
celldisp(names)

Thank you for your answer. It worked, I had to make a small change

names = {Files_cal(:).name} ; % I removed the space between Files_cal and (:)