Why do logical indices implicitly reshape? Is there a workaround?
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I've encountered this several times, and it always bothers me. Say for example I want to sum each row of matrix A, for values less than 0.5:
A = rand(3);
B = zeros( size(A) );
B(A<0.5) = A(A<0.5);
row_sum = sum( B, 2 );
But it feels like I should be able to simplify this, with something like:
row_sum = sum( A(A<0.5), 2 );
but this obviously fails because while A<0.5 preserves shape, A(A<0.5) returns a vector where the A<0.5 matrix is implicitly linearized.
I get why this happens (A>0.5 elements would be undefined in a matrix), but it seems incongruous with how logical indices are presented to the user as shape-preserving operations. After all, A<0.5 returns a logical matrix and you would need to call find(A<0.5) to acess the linear indices used to generate A(A<0.5).
In my humble opinion, it seems like this is exactly what NaN should exist for. If the default behavior of A(A<0.5) was to return NaN for A(A>0.5), then having functions like sum with 'omitnan' enabled by default would produce more intuitive results. Am I missing something?
Getting back to earth, are there any practical ways to simplify the above process?
4 个评论
Stephen23
2021-8-3
编辑:Stephen23
2021-8-3
"I think I'm missing something..."
When selecting a subset of array-elements, then these cannot maintain the same shape as the array that they are selected from. The introductory examples here
explains this as "MATLAB matches the locations of the value 1 in ind to the corresponding elements of A and B, and lists their values in a column vector." So the introductory tutorials do not imply "shape preserving". Nor does this more detailed article:
which states "The output is always in the form of a column vector."
This blog page
explains "The logical indexing expression C(D) extracts all the values of Ccorresponding to nonzero values of D and returns them as a column vector."
Can you please give a reference to the MATLAB documentation where "... logical indices are presented to the user as shape-preserving operations", as you wrote in your question.
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Jakeb Chouinard
2021-8-3
编辑:Jakeb Chouinard
2021-8-3
Assuming that modifying A is not allowed, I think you're close to the most simple way to do what you need.
You could also do something like:
A = rand(3);
B = A;
B(B<0.5) = 0; %or NaN, if that's preferred
sum(B,2)
Or:
A = rand(3);
cmpMatrix = A>=0.5; %CoMParison Matrix
sum(A.*cmpMatrix,2)
2 个评论
Jakeb Chouinard
2021-8-3
编辑:Jakeb Chouinard
2021-8-3
That's the spirit! At least then you're using up less space, though if you'll need to call the comparison matrix again, you may be better off keeping it stored. And just since I know the mods prefer to have questions be closed once answered, could you select my response as an accepted answer?
Cheers!
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