For loop only accesses the last element in an array

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Soeun Lee 2021-8-6

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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/893417-for-loop-only-accesses-the-last-element-in-an-array

评论： Stephen23 2021-8-6

Hi all,

I have an array CHANNEL[10 58 27], and I want my for loop to access all three elements. However, right now when I look at the value of di in my workspace, it says 27, so I'm assuming that it is only accessing the last element of the array.

How should I fix the code so that di accesses all three elements in the array?

for di=CHANNEL(1,:)
    %load (append('210603_bare-210727-182826','ch',string(di)))
    neural = timetable(RawData,'SampleRate',fs);
    neural.Properties.VariableNames{1} = 'raw';
    neural.Properties.VariableUnits{1} = 'Volts';
    HighPass = 300;
    LowPass = 5000;
    [Z, P, K] = butter(5, [HighPass LowPass]/(fs/2), "bandpass");
    sos = zp2sos(Z, P, K);
    neural.raw = double(neural.raw);
    neural.spikes = sosfilt(sos,RawData);
    
    for idx=1:length(CHANNEL)
        figure;
        nexttile;
        plot(neural.Time,neural.spikes(:,idx))
    end
    
    xlim([duration(0,init_mn,init_s,init_ms) duration(0,end_mn,end_s,end_ms)])
    ylim([-1e-4 1e-4])
end

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Peter Perkins 2021-8-6

This post exactly duplicates https://www.mathworks.com/matlabcentral/answers/893447-why-do-i-obtain-identical-graphs-while-for-loop-is-accessing-different-sets-of-data-stored-in-differ.

Stephen23 2021-8-6

在 MATLAB Online 中打开

@Soeun Lee: it might have something to do with your looping over the same vector in nested loops:

for di=CHANNEL(1,:)
    ...
    for idx=1:length(CHANNEL)
        figure;
        nexttile;
        plot(neural.Time,neural.spikes(:,idx))
    end
    ...
end