Symbollically solving Ax=b
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For example solve:
[a,b;c,d]*[x1;x2] = [b1;b2]
Matlab should return:
x1 = -(b*b2-d*b1)/(ad-bc) x2 = (a*b2 -c*b1)/(ad-bc)
thanks for your help,
回答（1 个）
Shashank Prasanna
2013-10-7
It does.
>> syms a b c d x1 x2 b1 b2
>> x = solve([a,b;c,d]*[x1;x2]==[b1;b2])
>> x.x1
>> x.x2
You can start here:
Check the documentation and post your attempt for quick, better response.
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2013-10-7
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