plot phase angle in radian
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subplot(2,2,1)
%chi=1; alpha=2; lambda=0.25
%eta=0
p1=0.00139;
%eta=10
p2=-0.01262;
theta_rad = p1*pi/180; % Degrees-To-Radians
polar(theta_rad, 'r.')
%title('Phase Angle')
title('$\chi=1.0, \quad \eta=0.0$','Interpreter','latex','FontSize',10,'FontName','Times New Roman','FontWeight','Normal')
%==========================================================
subplot(2,2,2)
theta_rad = p2*pi/180; % Degrees-To-Radians
polar(theta_rad, 'r.')
%title('Phase Angle')
title('$ \chi=1.0, \quad \eta=10.0$','Interpreter','latex','FontSize',10,'FontName','Times New Roman','FontWeight','Normal')
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
subplot(2,2,3)
%alpha=2; lambda=0.25
%eta=0
p3=0.02877;
%eta=10
p4=0.25253;
theta_rad = p3*pi/180; % Degrees-To-Radians
polar(theta_rad, 'r.')
%title('Phase Angle')
title('$\chi=10.0, \quad \eta=0.0$','Interpreter','latex','FontSize',10,'FontName','Times New Roman','FontWeight','Normal')
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
subplot(2,2,4)
theta_rad = p4*pi/180; % Degrees-To-Radians
polar(theta_rad, 'r.')
%title('Phase Angle')
title('$ \chi=10.0, \quad \eta=10.0$','Interpreter','latex','FontSize',10,'FontName','Times New Roman','FontWeight','Normal')
6 个评论
Walter Roberson
2021-8-9
I am not sure what the question is? Are you asking to have the polar plot labeled in radians instead of degrees?
I recalculate the above as the following? my question now what are the values that appear on the figure
subplot(2,2,1)
%chi=1; alpha=2; lambda=0.25
%eta=0
p1=0.00139;
%eta=10
p2=-0.01262;
theta_rad = p1*pi/180; % Degrees-To-Radians
polar(theta_rad, 'r.')
%title('Phase Angle')
title('$\chi=1.0, \quad \eta=0.0$','Interpreter','latex','FontSize',10,'FontName','Times New Roman','FontWeight','Normal')
%==========================================================
subplot(2,2,2)
theta_rad = p2*pi/180; % Degrees-To-Radians
polar(theta_rad, 'r.')
%title('Phase Angle')
title('$ \chi=1.0, \quad \eta=10.0$','Interpreter','latex','FontSize',10,'FontName','Times New Roman','FontWeight','Normal')
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
subplot(2,2,3)
%alpha=2; lambda=0.25
%eta=0
p3=0.02877;
%eta=10
p4=0.25253;
theta_rad = p3*pi/180; % Degrees-To-Radians
polar(theta_rad, 'r.')
%title('Phase Angle')
title('$\chi=10.0, \quad \eta=0.0$','Interpreter','latex','FontSize',10,'FontName','Times New Roman','FontWeight','Normal')
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
subplot(2,2,4)
theta_rad = p4*pi/180; % Degrees-To-Radians
polar(theta_rad, 'r.')
%title('Phase Angle')
title('$ \chi=10.0, \quad \eta=10.0$','Interpreter','latex','FontSize',10,'FontName','Times New Roman','FontWeight','Normal')
Shreen El-Sapa
2021-8-9
Walter Roberson
2021-8-9
Yes?
You are using polar() with a single parameter. The default when you pass a single parameter to polar() is to treat the input as radii, with equally-spaced angles (dividing a full circle by the number of radii passed in.)
The numbers you outlined in yellow are the radii you passed in. You converted some input value to radians according to your comments, so the radius of each polar plot represents radians for something. That all seems like something that you might want to do, so I do not see what you would like to have happen differently ?
Shreen El-Sapa
2021-8-9
Walter Roberson
2021-8-9
To be more correct, the yellow numbers are linear spaced from 0 to the maximum value you asked to plot.
回答（1 个）
Walter Roberson
2021-8-9
0 个投票
If the question is about switching the polar plot degrees to radians, then change your calls to polar() to instead be calls to polarplot(), and set the option 'ThetaAxisUnits', 'radians'
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