plot phase angle in radian

Question

Shreen El-Sapa 2021-8-8

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/894817-plot-phase-angle-in-radian

评论： Walter Roberson 2021-8-9

subplot(2,2,1)
%chi=1; alpha=2; lambda=0.25
%eta=0
p1=0.00139;
%eta=10
p2=-0.01262;
theta_rad = p1*pi/180;               % Degrees-To-Radians
polar(theta_rad, 'r.')
%title('Phase Angle')
title('$\chi=1.0, \quad \eta=0.0$','Interpreter','latex','FontSize',10,'FontName','Times New Roman','FontWeight','Normal')
%==========================================================
subplot(2,2,2)
theta_rad = p2*pi/180;               % Degrees-To-Radians
polar(theta_rad, 'r.')
%title('Phase Angle')
title('$ \chi=1.0, \quad \eta=10.0$','Interpreter','latex','FontSize',10,'FontName','Times New Roman','FontWeight','Normal')
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
subplot(2,2,3)
%alpha=2; lambda=0.25
%eta=0
p3=0.02877;
%eta=10
p4=0.25253;
theta_rad = p3*pi/180;               % Degrees-To-Radians
polar(theta_rad, 'r.')
%title('Phase Angle')
title('$\chi=10.0, \quad \eta=0.0$','Interpreter','latex','FontSize',10,'FontName','Times New Roman','FontWeight','Normal')
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
subplot(2,2,4)
theta_rad = p4*pi/180;               % Degrees-To-Radians
polar(theta_rad, 'r.')
%title('Phase Angle')
title('$ \chi=10.0, \quad \eta=10.0$','Interpreter','latex','FontSize',10,'FontName','Times New Roman','FontWeight','Normal')

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Shreen El-Sapa 2021-8-9

编辑：Walter Roberson 2021-8-9

在 MATLAB Online 中打开

I recalculate the above as the following? my question now what are the values that appear on the figure

subplot(2,2,1)

%chi=1; alpha=2; lambda=0.25

%eta=0

p1=0.00139;

%eta=10

p2=-0.01262;

theta_rad = p1*pi/180; % Degrees-To-Radians

polar(theta_rad, 'r.')

%title('Phase Angle')

title('$\chi=1.0, \quad \eta=0.0$','Interpreter','latex','FontSize',10,'FontName','Times New Roman','FontWeight','Normal')

%==========================================================

subplot(2,2,2)

theta_rad = p2*pi/180; % Degrees-To-Radians

polar(theta_rad, 'r.')

%title('Phase Angle')

title('$ \chi=1.0, \quad \eta=10.0$','Interpreter','latex','FontSize',10,'FontName','Times New Roman','FontWeight','Normal')

%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%

subplot(2,2,3)

%alpha=2; lambda=0.25

%eta=0

p3=0.02877;

%eta=10

p4=0.25253;

theta_rad = p3*pi/180; % Degrees-To-Radians

polar(theta_rad, 'r.')

%title('Phase Angle')

title('$\chi=10.0, \quad \eta=0.0$','Interpreter','latex','FontSize',10,'FontName','Times New Roman','FontWeight','Normal')

%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%

subplot(2,2,4)

theta_rad = p4*pi/180; % Degrees-To-Radians

polar(theta_rad, 'r.')

%title('Phase Angle')

title('$ \chi=10.0, \quad \eta=10.0$','Interpreter','latex','FontSize',10,'FontName','Times New Roman','FontWeight','Normal')

Shreen El-Sapa 2021-8-9

I asked about the highlighted numbers only. you clearified.Thanks.

Walter Roberson 2021-8-9

To be more correct, the yellow numbers are linear spaced from 0 to the maximum value you asked to plot.

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Answer 1

Walter Roberson 2021-8-9

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/894817-plot-phase-angle-in-radian#answer_763417

If the question is about switching the polar plot degrees to radians, then change your calls to polar() to instead be calls to polarplot(), and set the option 'ThetaAxisUnits', 'radians'

https://www.mathworks.com/help/matlab/ref/matlab.graphics.axis.polaraxes-properties.html#bu8f1sf_sep_shared-ThetaAxisUnits