plot phase angle in radian
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subplot(2,2,1)
%chi=1; alpha=2; lambda=0.25
%eta=0
p1=0.00139;
%eta=10
p2=-0.01262;
theta_rad = p1*pi/180; % Degrees-To-Radians
polar(theta_rad, 'r.')
%title('Phase Angle')
title('$\chi=1.0, \quad \eta=0.0$','Interpreter','latex','FontSize',10,'FontName','Times New Roman','FontWeight','Normal')
%==========================================================
subplot(2,2,2)
theta_rad = p2*pi/180; % Degrees-To-Radians
polar(theta_rad, 'r.')
%title('Phase Angle')
title('$ \chi=1.0, \quad \eta=10.0$','Interpreter','latex','FontSize',10,'FontName','Times New Roman','FontWeight','Normal')
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
subplot(2,2,3)
%alpha=2; lambda=0.25
%eta=0
p3=0.02877;
%eta=10
p4=0.25253;
theta_rad = p3*pi/180; % Degrees-To-Radians
polar(theta_rad, 'r.')
%title('Phase Angle')
title('$\chi=10.0, \quad \eta=0.0$','Interpreter','latex','FontSize',10,'FontName','Times New Roman','FontWeight','Normal')
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
subplot(2,2,4)
theta_rad = p4*pi/180; % Degrees-To-Radians
polar(theta_rad, 'r.')
%title('Phase Angle')
title('$ \chi=10.0, \quad \eta=10.0$','Interpreter','latex','FontSize',10,'FontName','Times New Roman','FontWeight','Normal')
6 个评论
Walter Roberson
2021-8-9
To be more correct, the yellow numbers are linear spaced from 0 to the maximum value you asked to plot.
回答(1 个)
Walter Roberson
2021-8-9
If the question is about switching the polar plot degrees to radians, then change your calls to polar() to instead be calls to polarplot(), and set the option 'ThetaAxisUnits', 'radians'
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