how can a make a loop for a double value in Matlab?

Question

DulceEien 2021-8-10

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评论： DulceEien 2021-8-10

when I obtain the data for the array I'm having the ID in a 22x1 double data, and when I run the if condition I have a problem with the size

"Unable to perform assignment because the indices on the left side are not compatible with the size of the right side."

for i = 1:length(T1.ID)
    if ID(i) == 0
        EI(i) = 'Very high';
    elseif ID(i) == 1
        EI(i) = 'High';
    elseif ID(i) == 2
        EI(i) = 'Medium';
    elseif ID(i) == 3
        EI(i) = 'Low';
    end
end

the other values are taking a colum of the table generated. Sorry, I'm kind of new with matlab, thanks in advance

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Answer 1

Simon Chan 2021-8-10

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I think it should put into a cell array:

EI = cell(1,length(T1.ID));                         % Cell array
for i = 1:length(T1.ID)
    if ID(i) == 0
        EI{i} = 'Very high';
    elseif ID(i) == 1
        EI{i} = 'High';
    elseif ID(i) == 2
        EI{i} = 'Medium';
    elseif ID(i) == 3
        EI{i} = 'Low';
    end
end

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DulceEien 2021-8-10

yes, this is working, thank yoou

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Answer 2

Scott MacKenzie 2021-8-10

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在 MATLAB Online 中打开

It's not clear what 19 variables you have in the table T1, but I suspect your error will disappear via...

for i = 1:length(ID) % change from T1.ID to just ID
    if ID(i) == 0
        EI(i) = 'Very high';
    elseif ID(i) == 1
        EI(i) = 'High';
    elseif ID(i) == 2
        EI(i) = 'Medium';
    elseif ID(i) == 3
        EI(i) = 'Low';
    end
end