How to create column headers?

Question

Hannah 2021-8-13

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/897777-how-to-create-column-headers

评论： Hannah 2021-8-16

I have the following code:

months=1:12;
orientation = [0, -90];
row = 1:3;
tilt = [0,10,20,30,40,50,60,70,80,90];
irr = [10,110,120,130,140,150,160,170,180,190];
table.x=tilt;
table.y=irr;
for m=1:length(months)
    for o=1:length(orientation)
        for r=1:length(row)
            disp([m,o,r])
            for n=1:length(tilt)
table.x=tilt(n);
table.y=irr(n);
disp(table)
            end 
        end 
    end 
end 

How can I have x and y as the column headers instaed of having them noting every element? for example for m=1,0=2,r=3, I want the output to be:

1 2 3

x y

0 10

10 110

20 120

30 130

40 140

50 150

60 160

70 170

80 180

90 190

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Answer 1

Scott MacKenzie 2021-8-13

1
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/897777-how-to-create-column-headers#answer_766367

编辑：Scott MacKenzie 2021-8-13

在 MATLAB Online 中打开

Something like this will work. I'm only showing the inner for-loop.

    fprintf('%6s%6s\n\n', 'x', 'y');
    for n=1:length(tilt)
         table.x=tilt(n);
         table.y=irr(n);
         disp([table.x table.y]);           
    end    

Output (last table only):

12 2 3

x y

0 10

10 110

20 120

30 130

40 140

50 150

60 160

70 170

2 个评论
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Hannah 2021-8-13

That's perfect! thank you so much :)

Scott MacKenzie 2021-8-13

You're welcome. Glad to help. Good luck.

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Answer 2

Cris LaPierre 2021-8-13

1
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/897777-how-to-create-column-headers#answer_766377

在 MATLAB Online 中打开

My preference is to use the table function to create a MATLAB table (data type table instead of structure)

x = [0,10,20,30,40,50,60,70,80,90]';
y = [10,110,120,130,140,150,160,170,180,190]';
data = table(x,y)
data = 10×2 table
    x      y 
    __    ___

     0     10
    10    110
    20    120
    30    130
    40    140
    50    150
    60    160
    70    170
    80    180
    90    190

However, to stick to the same approach you are using, remove the last loop. I've reduced months and row to limit the output length here.

months=1:1;
orientation = [0, -90];
row = 1:1;
tilt = [0,10,20,30,40,50,60,70,80,90];
irr = [10,110,120,130,140,150,160,170,180,190];
for m=1:length(months)
    for o=1:length(orientation)
        for r=1:length(row)
            disp([m,o,r])
            table.x=tilt';
            table.y=irr';
            disp(["x","y"])
            disp([table.x table.y])
        end
    end
end
     1     1     1
    "x"    "y"
     0    10
    10   110
    20   120
    30   130
    40   140
    50   150
    60   160
    70   170
    80   180
    90   190
     1     2     1
    "x"    "y"
     0    10
    10   110
    20   120
    30   130
    40   140
    50   150
    60   160
    70   170
    80   180
    90   190

To create exactly what you specified, you can use fprintf instead of disp

for m=1:length(months)
    for o=1:length(orientation)
        for r=1:length(row)
            fprintf('%g    %g    %g',m,o,r)
            fprintf('%s    %s',"x","y")
            table.x=tilt';
            table.y=irr';
            fprintf('%g    %g\n',[table.x table.y]')
        end
    end
end
1    1    1
x    y
0    10
10    110
20    120
30    130
40    140
50    150
60    160
70    170
80    180
90    190
1    2    1
x    y
0    10
10    110
20    120
30    130
40    140
50    150
60    160
70    170
80    180
90    190