How to plot using a loop on the same axis

16 次查看(过去 30 天)
Would like to plot without having to hard code every single line up to 20+ customers(20 x 1 structure). Had an attempt at a for loop, the error message states that the number of element on the right are not same as on the left
%Graphical representation
t = 0:0.1:310; % Time vector for plots (m)
[position1,speed1,Duration1] = calcFallForPerson(customer(1),4200,0.1,1500);
[position2,speed2,Duration2] = calcFallForPerson(customer(2),4200,0.1,1500);
[position3,speed3,Duration3] = calcFallForPerson(customer(3),4200,0.1,1500);
[position4,speed4,Duration4] = calcFallForPerson(customer(4),4200,0.1,1500);
figure(1)
plot(t,position1,t,position2,t,position3,t,position4)
title('Posiion')
xlabel('Time(s)')
ylabel('Postion(m)')
xlim([0 320])
ylim([0 4500])
figure(2)
plot(t,speed1,t,speed2,t,speed3,t,speed4)
title('Velocity')
xlabel('Time(s)')
ylabel('Velocity(m/s)')
xlim([0 320])
ylim([0.0 60.0])
xlim([0 320])
ylim([0.0 60.0])

采纳的回答

Wan Ji
Wan Ji 2021-8-14
Is the time array t the same size as position1,speed1 for each loop with different customers? If so, then following loop will help you!
t = 0:0.1:310; % Time vector for plots (m)
number_of_customer = 20; % change as you want
[position,speed,Duration] = arrayfun(@(i)acalcFallForPerson(customer(i),4200,0.1,1500),...
1:1:number_of_customer, 'uniform', false);
figure(1)
arrayfun(@(i)plot(t,position{i}),1:1:number_of_customer);
title('Posiion')
xlabel('Time(s)')
ylabel('Postion(m)')
xlim([0 320])
ylim([0 4500])
figure(2)
arrayfun(@(i)plot(t,speed{i}),1:1:number_of_customer);
title('Velocity')
xlabel('Time(s)')
ylabel('Velocity(m/s)')
xlim([0 320])
ylim([0.0 60.0])
xlim([0 320])
ylim([0.0 60.0])

更多回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Loops and Conditional Statements 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by