How do I create a vector of the average of consecutive elements of another vector (without using a loop)?
显示 更早的评论
Say, I have a vector A=[2 4 6 8 10]. Is there any way I can create a vector of the average of consecutive elements of A, i.e. B=[3 5 7 9] without using a loop? Is there any matlab function to do that? Thanks in advance.
采纳的回答
Azzi Abdelmalek
2013-10-10
编辑：Azzi Abdelmalek
2013-10-10
A=[2 4 6 8 10]
B=mean([A(1:end-1);A(2:end)])
更多回答（2 个）
This is simpler and occupies less temporary memory than Azzi's approach:
A = [2 4 6 8 10];
B = 0.5 * (A(1:end-1) + A(2:end))
Matthew Crema
2013-10-10
One way:
A=[2 4 6 8 10];
foo = conv([1 1], A)/2;
B = foo(2:end-1)
B =
3 5 7 9
-Matt
5 个评论
Rinu
2013-10-10
Jan
2013-10-10
Instead of dividing the array after the application of conv, you can divide the parameters instead: conv([0.5, 0.5], A) . The avoids the expensive division of all array elements.
Matthew Crema
2013-10-11
Yup. But I agree that the use of indexing seems better with respect to readability and marginally better speed.
Jan
2013-10-11
The speed argument might change, when the data exceed a certain size.
Andrei Bobrov
2013-10-11
编辑：Andrei Bobrov
2013-10-11
conv2(A,[.5 .5],'valid')
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