I do not think that you can create such a matrix because there is a column dimension mis-match. You can add zero padding to get such a result
A = [1 2 3 4 5];
B = [3 5 1 4];
M = [0 1 1 0 0;1 1 0 0 1;0 1 0 1 0;0 1 1 0 1];
M = horzcat(B',M); % horizonal concatenation
% size(A,2) is not equal to size(M,2). To make them equal add zeros in A
M = vertcat([zeros(1,length(M)-length(A)) A],M) % vertical concatenation
