change a cell having 3-dimenisional matrix into a 2-dimenisional matrix

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som
som 2013-10-11
评论： som 2013-10-13
Hi all,
I have a variable named "z" which has the 2-dimensional cell structure like following program:
for tt=1:3
for nn=1:4
z{tt,nn}=rand(2,3,4);
end
end
z =
[2x3x4 double] [2x3x4 double] [2x3x4 double] [2x3x4 double]
[2x3x4 double] [2x3x4 double] [2x3x4 double] [2x3x4 double]
[2x3x4 double] [2x3x4 double] [2x3x4 double] [2x3x4 double];
assume the value of z at tt=1 and nn=1 , i.e. z{1,1}, is qual below: z{1,1}
val(:,:,1) =
0.8147 0.1270 0.6324
0.9058 0.9134 0.0975
val(:,:,2) =
0.2785 0.9575 0.1576
0.5469 0.9649 0.9706
val(:,:,3) =
0.9572 0.8003 0.4218
0.4854 0.1419 0.9157
val(:,:,4) =
0.7922 0.6557 0.8491
0.9595 0.0357 0.9340
z{2,1} =
val(:,:,1) =
0.6880 0.5716 0.8095
0.2968 0.3162 0.3655
val(:,:,2) =
0.6988 0.9646 0.5982
0.6334 0.2008 0.0837
val(:,:,3) =
0.5444 0.0407 0.7093
0.8461 0.3294 0.8603
val(:,:,4) =
0.5009 0.4286 0.4730
0.9948 0.2673 0.1608
z{3,1} =
val(:,:,1) =
0.1589 0.7571 0.9669
0.2683 0.6092 0.7733
val(:,:,2) =
0.5729 0.2871 0.0944
0.4502 0.7524 0.1068
val(:,:,3) =
0.7349 0.5806 0.7137
0.3546 0.2989 0.3605
val(:,:,4) =
0.7185 0.0837 0.0938
0.9953 0.4682 0.7252
and so on.
I want to put all elements of z into a matrix and make a new matrix named "zz" whose size is 24*9. for example the zz(:, 1:3) is like below:
zz(:,1:3)=[0.8147 0.1270 0.6324;
0.9058 0.9134 0.0975;
0.2785 0.9575 0.1576;
0.5469 0.9649 0.9706;
0.9572 0.8003 0.4218;
0.4854 0.1419 0.9157;
0.7922 0.6557 0.8491;
0.9595 0.0357 0.9340;
0.6880 0.5716 0.8095;
0.2968 0.3162 0.3655;
0.6988 0.9646 0.5982;
0.6334 0.2008 0.0837;
0.5444 0.0407 0.7093;
0.8461 0.3294 0.8603;
0.5009 0.4286 0.4730;
0.9948 0.2673 0.1608;
0.1589 0.7571 0.9669;
0.2683 0.6092 0.7733;
0.5729 0.2871 0.0944;
0.4502 0.7524 0.1068;
0.7349 0.5806 0.7137;
0.3546 0.2989 0.3605;
0.7185 0.0837 0.0938;
0.9953 0.4682 0.7252;]
How can I do it? following is any help whould be appreciated. Thanks in advance.

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回答（1 个）

Matt J
Matt J 2013-10-11
zz=reshape( cat(2,z{:}) ,[],9);
  3 个评论
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Matt J
Matt J 2013-10-13
I think you need to redo the description of what you want. There are 288 doubles total contained across z, yet you claim to want a final matrix zz that is 24x9, which would contain only 216 elements. We also cannot see what data order you want when you only show the first 3 columns of zz.
som
som 2013-10-13
ok, thanks for your response. I have explained my question more clearly through a new question. you can see it soon. I would be thankful if you take a look at that question and give me your feedback.

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