Cell contents assignment to a non-cell array object.
2 次查看(过去 30 天)
显示 更早的评论
Hey guys,
i do have this little code to program. what i dont understand is, when i run it without the inner for-loop, there is now error. when i run with the loop, there is this error that i dont understand. Anybody able to help me finding the bug ?
C = cell(28, 1);
for i=1:1:28;
C{i} = UM(i,:);
IPV = C{i,1}(1);
IB = C{i,1}(2);
IWP = C{i,1}(3);
IK = C{i,1}(4);
IWS = C{i,1}(5);
for p = 1:1:2;
Bundesland=p;
OptimierungPV_B_WP_mitWaermespeicher_Bandu_14;
Kapitalwert(1,1) = num2cell(ZFW);
if Bundesland == 1;
xlswrite('testsheet.xlsx', ...
Kapitalwert, ...
'Kapitalwerte','A1:A28');
elseif Bundesland == 2;
xlswrite('testsheet.xlsx', ...
Kapitalwert, ...
'Kapitalwerte','B1:B28');
end;
end;
end;
3 个评论
Walter Roberson
2013-10-12
The line with problems is likely
Kapitalwert(1,1) = num2cell(ZFW);
which would be a problem if Kapitalwert exists but was not a cell array at the time of the assignment.
采纳的回答
Michael
2013-10-14
1 个评论
Walter Roberson
2013-10-14
Ah. Usually we assume that calls to user routines are functions unless they are clearly scripts.
更多回答(1 个)
Michael
2013-10-14
1 个评论
Walter Roberson
2013-10-14
The code you give is not going to have a problem at C{i} = UM(i,:) even if UM is a cell array. Not unless there is some additional code you have not shown, between the C = cell(28,1); and the code you show.
另请参阅
类别
在 Help Center 和 File Exchange 中查找有关 Matrices and Arrays 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!