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new array using average row of the old array

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babis
babis 2013-10-13
评论： babis 2013-10-13
I have an array M(1000,1000) and i want to build a new array N(1000,1000), where each element of N has the old value minus the average of its row (in M). If the element is zero no action will be taken. Also, from the average the zeros should be excluded.
Can you help me?
thank you in advance

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采纳的回答

Azzi Abdelmalek
Azzi Abdelmalek 2013-10-13
编辑：Azzi Abdelmalek 2013-10-13
Edit
out=bsxfun(@minus,M,mean(M,2)).*not(~M)
%or
idx=M==0;
out=bsxfun(@minus,M,mean(M,2));
out(idx)=0
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Azzi Abdelmalek
Azzi Abdelmalek 2013-10-13
编辑：Azzi Abdelmalek 2013-10-13
Ok try this
idx=M==0;
moyenne=sum(M,2)./sum(not(~M),2)
out=bsxfun(@minus,M,moyenne)
out(idx)=0

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更多回答（1 个）

Andrei Bobrov
Andrei Bobrov 2013-10-13
ii = M == 0;
out = bsxfun(@minus,M,sum(M,2)./sum(~ii,2));
out(ii) = 0;

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