how to read a text file and read it line by line?

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I have a text file which contains these sample of data in each line:
11-11111
11-25519
32-68129
36-14111
and I need to compare a number like these in the program with each line. for example in the program there is the number 14-68129 and there is no much in the file for it. how can I do this. the name of file is 'num.txt'. thanks
  2 个评论
Cedric
Cedric 2013-10-14
编辑:Cedric 2013-10-14
So white spaces separate numbers, and dashes are some sort of internal separators, which play a role comparable to the decimal point? And are you checking each line of the file for the presence of one of these composite numbers (like 14-68129), or do you have a set of numbers? Finally, what information do you need? Just a flag that indicates the presence in the file, a flag per line, a count per line, a count for the whole file?

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采纳的回答

sixwwwwww
sixwwwwww 2013-10-14
Dear Behrad, here is the complete code for your problem:
fid = fopen(filename); % Insert here the file name with complete file path
cell_data = textscan(fid, '%s');
fclose(fid);
matrix_data = [cell_data{:}];
Codes = char(matrix_data{:});
A = abs(Codes);
[m, n] = size(A);
new_code = '36-14111'; % Insert here your value you want to search in file
B = abs(new_code);
Codestatus = 0;
for i = 1:m
if A(i, :) == B(1,:)
disp('Code found')
Codestatus = 1;
break;
end
end
if Codestatus == 0
disp('Code not found')
end
Good luck!

更多回答(2 个)

Cedric
Cedric 2013-10-14
编辑:Cedric 2013-10-14
If the string defining the composite number is stored in a variable named theNumber:
count = numel( strfind( fileread('num.txt'), theNumber )) ;
  1 个评论
Cedric
Cedric 2013-10-22
编辑:Cedric 2013-10-22
I guess that I should have made an example .. file Behrad.txt contains
11-11111
11-25519
14-68129
32-68129
14-68129
36-14111
14-68129
then,
>> count = numel( strfind( fileread('Behrad.txt'), '14-68129' ))
count =
3
and a count of 0 means "not found" obviously.

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Azzi Abdelmalek
Azzi Abdelmalek 2013-10-14
编辑:Azzi Abdelmalek 2013-10-14
v={'11-11111';'11-25519';'32-68129';'36-14111'}
n= '14-68129'
idx=find(strcmp(v,n))
%To read v
fid=fopen('num.txt')
v=textscan(fid,'%s')
fclose(fid)
  3 个评论
Behrad kiani
Behrad kiani 2013-10-22
thanks for your comment AZZI my internet access is very low and I couldn,t reply your comment. I found the answer below

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