Approximately equal or egual to +- error
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Hi,
I have two vectors where each has a column with approximately equal values like this:
Vector1 Vector2
1.11111 1.2222
1.12111 1.2238
... ...
1.2223 1.4446
Since the value of Vector1: 1.2223 is not exactly equal to the value of Vector2: 1.2222 I cannot use the equal to command to find the value 1.2223 in vector2.
What I'm looking for is a command or a way to find a value in vector2 that is approximately equal to a value from vector1 within some limits.
It could look like this:
find(vector2(:,1))=vector1(1,?)+-0.0001
Where +-0.0001 would be the limits. But you can't write it like this.
I'm thankful for any hint.
回答（4 个）
Andrei Bobrov
2011-6-8
u(abs(v - u)<=e)
index
idx = find(abs(v - u)<=e)
Paulo Silva
2011-6-8
Adapt this code to your purpose:
v=[1.1 2.2 3.3]' %vector 1
u=[1.2 2.6 6]' %vector 2
e=0.1 %error
u(u<=v+e & u>=v-e) %values in vector 2 that are inside the limits
%it only compares values in the same index number
1 个评论
Manjur Hossain
2021-5-7
Thank you Mr. Paulo Silva. You have post it at very earlier but I have implemented it today for my own work. Thank you for solution for nearest value.
Stefan
2011-6-8
0 个投票
2 个评论
Paulo Silva
2011-6-8
use the find function
doc find
Jan
2011-6-8
"L = abs(v - u)<=e" is the logical index, "find(L)" is the numerical index.
This is explained in the "Getting Started" chapters of the documentation.
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2021-5-7
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