how to write a sript for while loop and for loop. please include code

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leon leon
leon leon 2013-10-15
编辑： Walter Roberson 2013-10-15
Write a script that first asks the user for a number (using the input command).
Using an if statement, print out if this number is positive, negative or zero. Test
your script a few times to make sure it does the right thing for all three cases.
o Put a break point in each branch of the if statement
o Run the script and enter a negative number. Did you stop at the right
branch? If so, un-click that break point. Repeat with a positive number and
with zero to check that you visit all three if statement branches.
• Now copy your if statement and put it in a for loop that asks the user for input 10
times so you don’t have to keep calling the script by hand. Remember that
control-c will stop the loop.
• Now change the for loop to a while loop that stops when the user inputs zero.
What should your stopping condition be?
o Hint: There are two ways to do this. One is to declare a “flag” variable that
is set to false before you start the while loop, eg stop = 0; while stop ==
0… When you get an input that is zero, set stop to be true.
o Second approach: Suppose you are using n as the variable you store the
user’s input in (eg n = input(‘Type a number’)). Declare n before the start
of the while loop, setting it to some value other than zero. Then, check the
value of n.

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采纳的回答

ES
ES 2013-10-15
Homework ain't it?
InputNumber=input('enter the number');
%Do some checjks to validate if the input is valid here
if InputNumber>0
disp('Positive Number');
elif InputNumber<0
disp('Negative Number');
else
disp('Zero');
end
II
for loop1=1:10
nputNumber=input('enter the number');
%Do some checjks to validate if the input is valid here
if InputNumber>0
disp('Positive Number');
elif InputNumber<0
disp('Negative Number');
else
disp('Zero');
end
end
III
InputNumber=1;
while (loop1<10 && InputNumber~=0)
InputNumber=input('enter the number');
%Do some checjks to validate if the input is valid here
if InputNumber>0
disp('Positive Number');
elif InputNumber<0
disp('Negative Number');
end
end

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