assigning matrices to a cell
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Right I apologise in advance because I have the feeling that what I've done may be some awful mistake that makes people with more matlab experience shudder but the concept of cells are kind of new to me.
Essentially I have a loop that creates a matrix Y each time I run it and I want to store this for use later in the code so that I can compare its entries with another array that I've created (successfully I might add!). At first I thought about using 3D arrays but then I realised that this meant all the cells needed to be the same size. This is a stripped down version of the relevant section of my code...
for k=1:K2
Y=zeros(N,D);
for n=1:N
if (r(n,k)==1)
Y(n,:)=X(n,:);
end
end
for n=N:-1:1
if ((sum(Y(n,:)))==0)
Y(n,:)=[];
end
end
Y=sortrows(Y);
Bla_2{:,k}=Y;
end
Can anyone please explain what I've done wrong and please use simple language. Thanks.
采纳的回答
Andrei Bobrov
2011-6-9
help:
doc all
doc function_handle
doc arrayfun
cod:
l1 = all(X,2);
X1 = X(l1,:);
r1 = r(l1,:)==1;
Bla_2 = arrayfun(@(ii)X1(r1(:,ii),:),1:K2,'un',0);
4 个评论
Natalie
2011-6-9
Natalie
2011-6-9
Andrei Bobrov
2011-6-9
ii - the column index varies from 1 to K2.
arrayfun uses an anonymous function @ (ii) X1 (r1 (:, ii),:), for each ii, and places the result in a single cell cellarray (sorry for my english).
In this, the better to read the help on the functions -
"function_handle", "arrayfun".
Natalie
2011-6-9
更多回答（2 个）
Matt Fig
2011-6-8
Use:
Bla_2{k} = Y;
But before the outer loop starts, pre-allocate the cell array:
Bla_2 = cell(K2,1);
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