return or break in nested loop?
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Hi everybody,
I have written the codes below :
for i=1:25
if isempty(in_x)
return
else
int = int+1;
aa = in_x-in_x(1);
bb = find(aa>((SOP+SPH)*dsr/SL));
if isempty(bb)
return
else
int = int+1;
ll = in_x(bb(1):size(in_x,2))-in_x(bb(1));
bb2 = find(ll>((SOP+SPH)*dsr/SL));
if isempty(bb2)
return
else
int = int+1;
end
end
end
end
I wanna know why when the first condition satisfies, by the return command it goes to the last "end" which is not the corresponding "end" and it should go to the first "end".
is there any other command which i could use instead of return?
采纳的回答
David Young
2011-6-15
If your code is a script (not part of a function definition), then "return" returns control to the keyboard - that is, it is like a jump to the end of the script. So the answer to your first question is: it's doing what it is supposed to do.
The answer to your second question is yes, you could use the "break" command if you want to exit the inner loop. You mention this possibility in your question title.
If your problem is that you want to go to the next case if in_x is empty, then just simplify the code to
for i=1:25
if ~isempty(in_x)
int = int+1;
% etc.
end
end
But note that your code will need to do something to change the value of in_x on each iteration.
3 个评论
minoo
2011-6-15
David Young
2011-6-15
See the last part of my answer, which has a suggestion for this.
minoo
2011-6-15
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