return or break in nested loop?

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minoo
minoo 2011-6-15
Hi everybody,
I have written the codes below :
for i=1:25
if isempty(in_x)
return
else
int = int+1;
aa = in_x-in_x(1);
bb = find(aa>((SOP+SPH)*dsr/SL));
if isempty(bb)
return
else
int = int+1;
ll = in_x(bb(1):size(in_x,2))-in_x(bb(1));
bb2 = find(ll>((SOP+SPH)*dsr/SL));
if isempty(bb2)
return
else
int = int+1;
end
end
end
end
I wanna know why when the first condition satisfies, by the return command it goes to the last "end" which is not the corresponding "end" and it should go to the first "end".
is there any other command which i could use instead of return?
  1 个评论
minoo
minoo 2011-6-15
I mean my "for loop" ends when first condition satisfies, but i want to do this for 25 times for 25 different data sets.

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采纳的回答

David Young
David Young 2011-6-15
If your code is a script (not part of a function definition), then "return" returns control to the keyboard - that is, it is like a jump to the end of the script. So the answer to your first question is: it's doing what it is supposed to do.
The answer to your second question is yes, you could use the "break" command if you want to exit the inner loop. You mention this possibility in your question title.
If your problem is that you want to go to the next case if in_x is empty, then just simplify the code to
for i=1:25
if ~isempty(in_x)
int = int+1;
% etc.
end
end
But note that your code will need to do something to change the value of in_x on each iteration.
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David Young
David Young 2011-6-15
See the last part of my answer, which has a suggestion for this.
minoo
minoo 2011-6-15
thanks David for your help.it works well

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